10x^2+74x-3=0

Solution for 10x^2+74x-3=0 equation:

10x^2+74x-3=0

a = 10; b = 74; c = -3;
Δ = b2-4ac
Δ = 742-4·10·(-3)
Δ = 5596
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5596}=\sqrt{4*1399}=\sqrt{4}*\sqrt{1399}=2\sqrt{1399}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(74)-2\sqrt{1399}}{2*10}=\frac{-74-2\sqrt{1399}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(74)+2\sqrt{1399}}{2*10}=\frac{-74+2\sqrt{1399}}{20}
$